FREE()

void free(void *pointer);

 * the function name doesn't require any comments;
 * the function does not return any results so its type is defined as void;
 * the function expects one parameter – the pointer to the memory block that is to be 
   released; usually it’s a pointer previously received from the malloc or its 
   kindred; using another pointer value may cause some kind of disaster;
 * the function doesn't need to know the size of the freed block; you can only release 
   the entire allocated block, not a part of it;
 * after performing the free function, all the pointers that point to the data inside 
   the freed area become illegal; attempting to use them may result in abnormal
   program termination.